usb to serial port converter driver download

This width for all nuts up to 6 in. diameter of bolt may be found in any engineer's pocket-book. With the given width for the size of nut proposed to be drawn as a diameter, describe a circle in the HP at a convenient distance from the IL, and from the same centre a second circle equal in diameter to that of the bolt for which the nut is intended. Through the common centre of these circles draw lines indefinitely, parallel and perpendicular to the IL. Then with the T-square and set- 140 FIRST PRINCIPLES OF MECHANICAL AND ENGINEERING DRAWING 141 square of 60, draw lines tangential to the outer circle in the positions shown, and the resultant hexagon, with its inscribed circles, will be the plan of the intended nut when resting on the HP. To find its elevation in this position, project over into the YP the four corner edges of the nut seen when looked at in the direction of the arrow in plan. These will, of course, be lines perpendicular to the IL. Now, as the thickness, or height, of an ordinary nut generally equals the diameter of its bolt, set off this diameter as a height from the IL and through it draw a line parallel to the IL. This line will represent the top face of the nut, and were it a plane-faced one and not chamfered, its elevation would be completed by making this line to cut the four perpendiculars previously drawn in. The chamfering is represented in elevation by the three circular arcs and the two short lines at an angle of 45, tangent to the outer arcs, the reason for which will be fully explained when treating of screws, nuts, etc., later on. The plan and elevation of the nut being thus given, its projections as required in the problem are now to be found. Assuming the angle